In this guide
A circle question in SSC CGL often looks like a tangle of lines — chords crossing, tangents meeting outside, a quadrilateral drawn inside. But almost every one rests on one of about ten theorems. The trick is to recognise which one applies: is there an angle at the centre? A cyclic quadrilateral? A tangent meeting a radius? This post collects those theorems with worked examples.
Chords
- The perpendicular from the centre to a chord bisects the chord.
- Equal chords are equidistant from the centre.
- If a chord of length 2l is at distance d from the centre of a circle of radius r: r² = l² + d².
Worked example: A chord of length 16 cm is 6 cm from the centre. Find the radius.
r² = 8² + 6² = 100 → r = 10 cm.
Angles
| Theorem | Statement |
|---|---|
| Angle at the centre | The angle subtended at the centre is twice the angle at the circumference by the same arc |
| Same segment | Angles in the same segment are equal |
| Semicircle | The angle in a semicircle is 90° |
Worked example: An arc subtends 110° at the centre. Find the angle it subtends at a point on the remaining part of the circle.
110/2 = 55°.
Cyclic quadrilaterals
A quadrilateral whose vertices lie on a circle:
- Opposite angles sum to 180°.
- An exterior angle equals the interior opposite angle.
Worked example: In cyclic quadrilateral ABCD, ∠A = 3x and ∠C = 2x. Find x.
3x + 2x = 180 → x = 36.
Tangents
- A tangent is perpendicular to the radius at the point of contact.
- The two tangents from an external point are equal in length.
- Tangent length from a point at distance d from the centre: √(d² − r²).
Worked example: From a point 13 cm from the centre of a circle of radius 5 cm, find the length of the tangent.
√(169 − 25) = √144 = 12 cm.
Alternate segment theorem
The angle between a tangent and a chord equals the angle in the alternate segment.
Intersecting chords and secants
- Chords intersecting inside: if chords AB and CD meet at P, then PA × PB = PC × PD.
- Secants from an outside point: PA × PB = PC × PD, with each measured from P.
- Tangent and secant: PT² = PA × PB.
Worked example: From point P, a tangent PT and a secant PAB are drawn. PA = 4 cm and AB = 5 cm. Find PT.
PB = 9. PT² = 4 × 9 = 36 → PT = 6 cm.
Two circles
For two circles with radii r₁ and r₂ and centres d apart:
| Tangent | Length |
|---|---|
| Direct common tangent | √[d² − (r₁ − r₂)²] |
| Transverse common tangent | √[d² − (r₁ + r₂)²] |
Worked example: Two circles of radii 8 cm and 3 cm have centres 13 cm apart. Find the length of the direct common tangent.
√(169 − 25) = 12 cm.
Number of common tangents:
| Position | Common tangents |
|---|---|
| Far apart (d > r₁ + r₂) | 4 |
| Touching externally | 3 |
| Intersecting | 2 |
| Touching internally | 1 |
| One inside the other | 0 |
Incircle of a right triangle
For a right triangle with legs a and b and hypotenuse c, the inradius is r = (a + b − c)/2.
Worked example: Legs 6 and 8, hypotenuse 10: r = (6 + 8 − 10)/2 = 2.
Common traps
| Trap | Correct approach |
|---|---|
| Halving the wrong angle | The centre angle is double the circumference angle |
| Forgetting the right angle between tangent and radius | Mark it on your figure first |
| Confusing direct and transverse formulas | Direct: difference of radii; transverse: sum |
Practice
- Find the length of a chord that is 5 cm from the centre of a circle of radius 13 cm.
- In a cyclic quadrilateral, one angle is 75°. Find the opposite angle.
- Two tangents are drawn to a circle from an external point and the angle between them is 60°. Find the angle subtended by the chord of contact at the centre.
- Chords AB and CD intersect at P inside a circle. PA = 6, PB = 4 and PC = 3. Find PD.
- Two circles of radii 5 and 3 have centres 10 cm apart. Find the length of the transverse common tangent.
- Find the inradius of a right triangle with sides 5, 12 and 13.
Answers: 1. 24 cm. 2. 105°. 3. 120°. 4. 8. 5. 6 cm. 6. 2.
A note on dates and numbers. Exam patterns, vacancies and schedules change from year to year. Always confirm the current details in the latest notification on the Staff Selection Commission website .
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